99 Bottles of Beer: Unterschied zwischen den Versionen

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(update syntax)
Zeile 35: Zeile 35:
  # 99 bottles of beer in Python by Ricardo Garcia. Public Domain code.
  # 99 bottles of beer in Python by Ricardo Garcia. Public Domain code.
  # Fully compliant version, pretty indentation, fits in 80x24.
  # Fully compliant version, pretty indentation, fits in 80x24.
# small mods by enki
   
   
  plural = lambda n: "s" if n != 1 else ""
  plural = lambda n: "s" if n != 1 else ""
Zeile 52: Zeile 53:
  number(next(n)), plural(next(n)) )
  number(next(n)), plural(next(n)) )
   
   
  print "\n".join( verses(x) for x in range(99, -1, -1) )
  print "\n".join( verses(x) for x in xrange(99, -1, -1) )

Version vom 3. März 2007, 19:17 Uhr

99 bottles in Forth

99 bottles of beer on the wall, 99 bottles of beeeeer . . . , Take one down, pass it around, 98 bottles of beer on the wall. ...

| 99 Bottles of Beer in Reva Forth
| by Phantasus
: .bottle ( n -- n) dup 1 >if ." bottles of" space ;then ." bottle of" space ;
: .wall ( n -- n ) dup 0 >if dup . .bottle ." beer on the wall," cr ;then
 ." No more bottles of beer on the wall." cr 
;
: .beer ( n -- n ) dup . .bottle ." beeeeer . . . ," cr ;
: .take ( n -- n-1 ) ." Take one down, and pass it around," cr 1- ;
: 99beer ( -- ) 99 100 1 do .wall .beer .take .wall cr loop
  ." Time to buy more beer!" cr 
;
99beer

99 bottles in SPL

for (var i=99; i>=0; i--) {
  write("\n${i ? i : "No more"} bottle${i != 1 ? "s" : ""} of beer on the "
        "wall, ${i ? i : "no more"} bottle${i != 1 ? "s" : ""} of beer.\n");
  write(i>0 ? "Take one down and pass it around, " :
              "Go to the store and buy some more, ");
  write("${i ? i>1 ? i-1 : "no more" : 99} bottle${i == 2 ? "" : "s"} "
        "of beer on the wall.\n${i ? "" : "\n"}");
}

99 Bottles in Python

#!/usr/bin/env python
# 	99 bottles of beer in Python by Ricardo Garcia. Public Domain code.
# 	Fully compliant version, pretty indentation, fits in 80x24.
# small mods by enki

plural = lambda n: "s" if n != 1 else ""
number = lambda n: "No" if n == 0 else str(n)
next = lambda n: (n - 1) % 100

pu_line = lambda n: "Go to the store and buy some more" or	\
	      	     "Take one down, pass it around" if n == 0 

verses = lambda n:	"%s bottle%s of beer on the wall!\n"		\
			"%s bottle%s of beer!\n"			\
			"%s\n"						\
			"%s bottle%s of beer on the wall!\n" %		\
			(	number(n), plural(n),
			 	number(n), plural(n),
			 	pu_line(n),
			 	number(next(n)), plural(next(n))	)

print "\n".join( verses(x) for x in xrange(99, -1, -1) )